{"id":1469869,"date":"2024-12-29T12:17:37","date_gmt":"2024-12-29T14:17:37","guid":{"rendered":"https:\/\/teknomers.com\/fr\/championnat-du-monde-de-flechettes-en-direct-jeffrey-de-graaf-peut-se-preparer-a-un-affrontement-avec-michael-van-gerwen-maintenant-kevin-doets-en-action\/"},"modified":"2024-12-29T12:17:42","modified_gmt":"2024-12-29T14:17:42","slug":"championnat-du-monde-de-flechettes-en-direct-jeffrey-de-graaf-peut-se-preparer-a-un-affrontement-avec-michael-van-gerwen-maintenant-kevin-doets-en-action","status":"publish","type":"post","link":"https:\/\/teknomers.com\/fr\/championnat-du-monde-de-flechettes-en-direct-jeffrey-de-graaf-peut-se-preparer-a-un-affrontement-avec-michael-van-gerwen-maintenant-kevin-doets-en-action\/","title":{"rendered":"Championnat du monde de fl\u00e9chettes EN DIRECT | Jeffrey de Graaf peut se pr\u00e9parer \u00e0 un affrontement avec Michael van Gerwen, maintenant Kevin Doets en action"},"content":{"rendered":"\n<p>Avec Michael van Gerwen, au moins un N\u00e9erlandais est au quatri\u00e8me tour du Championnat du monde de fl\u00e9chettes. Le triple champion du monde affrontera lundi le N\u00e9erlandais Jeffrey de Graaf, vainqueur dimanche apr\u00e8s-midi face au Philippin Paolo Nebrida. Kevin Doets esp\u00e8re \u00e9galement se qualifier pour le quatri\u00e8me tour cet apr\u00e8s-midi face au Polonais Krzysztof Ratajski. Suivez-le en direct ci-dessous. Programme s\u00e9ance de l&#8217;apr\u00e8s-midi (meilleur de 7) : \u2022 Jeffrey de Graaf &#8211; Paolo Nebrida 4-1 \u2022 Kevin Doets &#8211; Krzysztof Ratajski (31) \u2022 Dimitri Van den Bergh (11) &#8211; Callan Rydz<br \/>\n<br \/><br \/>\n<br \/><a href=\"https:\/\/www.destentor.nl\/sport\/live-wk-darts-jeffrey-de-graaf-mag-zich-opmaken-voor-clash-met-michael-van-gerwen-nu-kevin-doets-in-actie~a6d4db22\/\" rel=\"nofollow noopener\" target=\"_blank\">ttn-fr-42<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Avec Michael van Gerwen, au moins un N\u00e9erlandais est au quatri\u00e8me tour du Championnat du monde de fl\u00e9chettes. Le triple champion du monde affrontera lundi le N\u00e9erlandais Jeffrey de Graaf, vainqueur dimanche apr\u00e8s-midi face au Philippin Paolo Nebrida. Kevin Doets esp\u00e8re \u00e9galement se qualifier pour le quatri\u00e8me tour cet apr\u00e8s-midi face au Polonais Krzysztof Ratajski. [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1469870,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[3],"tags":[1063,6375,84,506,751,216838,16319,16320,17344,50731,14161,617,401,1056,181,6122,2536],"class_list":["post-1469869","post","type-post","status-publish","format-standard","has-post-thumbnail","hentry","category-general","tag-action","tag-affrontement","tag-avec","tag-championnat","tag-direct","tag-doets","tag-flechettes","tag-gerwen","tag-graaf","tag-jeffrey","tag-kevin","tag-maintenant","tag-michael","tag-monde","tag-peut","tag-preparer","tag-van"],"_links":{"self":[{"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/posts\/1469869","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/comments?post=1469869"}],"version-history":[{"count":0,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/posts\/1469869\/revisions"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/media\/1469870"}],"wp:attachment":[{"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/media?parent=1469869"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/categories?post=1469869"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/teknomers.com\/fr\/wp-json\/wp\/v2\/tags?post=1469869"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}